F x ct B x ct 2 sin, (2b) where A and B are the amplitudes, φ and ψ are the phases, and λ is the wavelength of the wave Now the x and tdependent parts of the sinefunction arguments are often written as k x±ωt, and so we can identify the wave vector k as 1 As we shall see, the functions in Eq (1) are the general solutions to the wave. Assuming that you want to compute ∫∫s curl F · dS Note that C is the curve x^2 y^2 = 25 with z = 0 Parameterize this by r(t) = with t in 0, 2π. Then F′(x) = f(x) We begin by interpreting (2) geometrically Start with the graph of f(t) in the typlane Then F(x) represents the area under f(t) between a and x;.
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