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(f o g)(x) = f(g(x)) It means first find the value of g(x), then plug that as the variable into f(x) g(x) = x2 That's the only value given for g(x), in other words there's no x to plug into g(x) to spit out a number.

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Y′ p(t) y = g(t) What we will do is to multiply the equation through by a suitably chosen function µ(t), such that the resulting equation µ(t) y′ µ(t)p(t) y = µ(t)g(t) (*) would have integrateable expressions on both sides Such a function µ(t) is called an integrating factor. ・j ・・・・・n ^ Y 04 N10 ・`12 ・箠/title> A t B G C g ・j. Z z z f h q wu d od y h q x h f k u \ v oh u mh h s f r p h h s wk h x q g lv s x wh g lq j r i wk h r ii u r d g d g y h q wx u h lq y lwh v \ r x wr f olp e lq wr wk h g u ly h u.

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