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Ij ≤ t j for all j, x ij ∈ {0,1} for all i,j By relaxing the time constraints for the processors, we obtain the dual problem maximize q(µ) = Xm i=1 q i(µ) subject to µ ≥ 0, where for each i, q i(µ) = min P n j=1 xij=1 xij∈{0,1} j=1 (a ij µ jp ij)x ij − 1 m n j=1 t jµ j We can easily evaluate q i(µ) for each µ ≥ 0 In. # ( ) * , / 0 1 2 3 # $ % 4 5 6 7 & 8 9 1 ;. Simple and best practice solution for g=(xc)/x equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

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0 into y(t) and find the constant C in the general solution such that y(t 0) = y 0 The result, if it could be found, is a specific function (or functions) that satisfies both the given differential equation, and the condition that the point (t 0, y 0) is contained on its graph Such a problem where both an equation.

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