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*, *,%*,#0/1*2 %' 3 =@?BACDE FGIH 3J H 7KDLNMPO OQ R8S S T U V'W6XZYY \^_XZ\ ` V XbacV W'd)eCfcghCV'a^geCi fcd)Yj8geCi kmlonqpsrutvkmlonqw. B r g e g ?. 54 UNIT STEP FUNCTIONS AND PERIODIC FUNCTIONS 163 Example 524 Find L −1 e 4s 1 s4 Solution We know for F(s) = 6 s4 that f(t) = t3So L −1 e 4s 1 s4 1 6 L −1 e 4s 6 s4 1 6 u(t−4)( t−4) 3 We now solve a differential equation arising from a spring mass system.

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116 = H > B R G B D g Z F b g g h _ h e h ` d b y m g b \ _ j k b l _ l “ K \ B \ Z g J b e k d b”, L h f 53, K \I 1 1, F _ o Z g b a Z p b y, _ e _ d l j b n. “Helping you to get your children through the 11 Plus and into a school of your choice” Verbal Reasoning Type U Letter Relationships A B C D E F G H I J K L M. S d i f n , x , n k s f u " d " k Z I v k S j II e s a d k S u & l k f u (a) Only conclusion I is true/ d s o y f u " d " k I l g h g S a (b) Only conclusion II is true/ d s o y f u " d " k II l g h g S (c) Either conclusion I or II is true/;.

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F U C T V c ̒ʔ̃T C g A O j t I C X g A ł B Y A f B X A L b Y ܂ŁA C X g A S A t H g A O t B b N A R W Ȃǂ̑ ʂȃf U C T V c ̔ Ă ܂ B o Y ( A X g m ~ I A C X V g X u e B ). Proof lnexy = xy = lnex lney = ln(ex ·ey) Since lnx is onetoone, then exy = ex ·ey 1 = e0 = ex(−x) = ex ·e−x ⇒ e−x = 1 ex ex−y = ex(−y) = ex ·e−y = ex · 1 ey ex ey • For r = m ∈ N, emx = e z }m { x···x = z }m { ex ···ex = (ex)m • For r = 1 n, n ∈ N and n 6= 0, ex = e n n x = e 1 nx n ⇒ e n x = (ex) 1 • For r rational, let r = m n, m, n ∈ N. Hn s e) hk d hr t" iy x n k ,he p b tb t" tv ihb n z ,k T ib S Qb T t" ,h t, hj n tn kg h hs tf t k n iIpUKt ihb n z ,k T ib S hn s e) in ,y x U tb T t hb , z j"u dk hk c e k tj r UtC kz n k hg r T t S h h s tf t k n k og k C rn t"u sk ,hn H e V, h u ,hk y e Q, h ;t ig f hr t" hn s e) in ,y x tk vk hk cI,t Qhb hg C JhC ot ig f U tj r t C h, Uns e)k sT g n T t hS ,hg s h tk hr t" ,hc j.

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Ae Aeœ E µe A Ae C Aºœae Ae Aº E Vicjuan S A Aººa A Cs A C

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