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This is more a puzzle than it is a problem in mathematics That being the case you need to look at the pattern in the series Starting with the first letter in the series (letter A) every other following letter in the series is the next vowel, so every other letter beginning with the A should follow the pattern A, E, I, O, U. !l c HÍ \ &k b 0 4 _ 6õ 0¿ í Ç b n b 0i!l b Hõ I ¡ Ï å º b Y 8 K v 4 u r K S HÎ Q b p HÍ Â & _ ^ Hì S Hõ I ¡ Ï å º l b P Â 8p 4 u Z 8 C G \ @ ² 0 _ ^ Hì Z C \ î Hì Z 8 r M HÎ '¨ b 1" 8 \ K Z c >0!l 6 ~ r M HÎ >/!l % c HÍ ² Z b > _ P M (á 4B ò "á ¥ V I O G \ M HÎ G b!l c Ò b &k 5* _ v ^ Hì Z 8 r M. E C X g a (TOSHIBA) ̃V O C g i ꗗ l C ؃ L O ̍ I ̐ i ̒ A i X y b N A L O A x ȂǁA ܂ ܂ȏ w 肵 Ď Ƀs b ^ ̐ i ȒP ɒT o Ƃ ł ܂ B( LED, K p ( ő )10 `12 ).

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Proposition 121 Let r be a root of the equation (129) r2 ar b 0 Then erx is a solution to the homogeneous equation (1210) y ay by 0 Equation (129) is called the auxiliary equation of the differential equation (1210) To verify the proposition, let y erx so that y rerx y r2erx Substituting into equation (1210) (1211) r2erx are rx berx. Title Flyer Studiengang DS 2 Version 11 18pub Microsoft Publisher Author Michel Created Date 11/18/ PM.

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